Question

if tan theta = 5/12 find sec theta and sec theta + cosec theta where theta is acute​

Answer 1

Answer:

I hope my answer will help you.

Answer 2

Answer:

$sec\theta=\frac{13}{12}$   and  $sec\theta+cosec\theta=\frac{221}{60}$

Step-by-step explanation:

Given that

$tan\theta=\frac{5}{12}=\frac{opposite}{adjacent}$

$hypotenuse=\sqrt{opposite^{2}+adjacent^{2} }$

$hypotenuse=\sqrt {5^{2}+12^{2} }$

Therefore, hypotenuse = 13

$sec\theta+cosec\theta=\frac{hypotenuse}{adjacent} +\frac{hypotenuse}{opposite}$

                      $=\frac{13}{12} +\frac{13}{5}$

                      $=\frac{221}{60}$

Therefore,

$sec\theta=\frac{13}{12}$   and  $sec\theta+cosec\theta=\frac{221}{60}$