if tan theta = a/b, prove that asin 2theta +bcos 2theta =b
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Answer:
tan theta=a/b
sin theta/cos theta=a/b
b.sin theta = a.cos theta
asin2theta + bcos 2theta=
a.2sintheta.costheta + b(2cos^2theta - 1)
2(sin theta.bsin theta) + 2bcos^2theta - ,b
2.b.sin^2theta + 2.b.cos^2theta - b
2b(sin^2theta + cos^2theta) - b
2b - b = b=RHS
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