Question

the volome of 4 g h2 gas at ntp​

Answer 1

Answer:

44.8L

Explanation:

ONE MOL OF ANY GAS AT NTP OCCUPIES 22.4L.

1 MOL OF H2=2G

SO 4G HAS 2 MOL

VOL=2*22.4=44.8

Answer 2

Answer:44.8 litre

Explanation:

Number of moles = given mass /molar mass

N=4/2

=2g

N=volume at ntp/22.4

2=volume at ntp/22.4

2×22.4=volume at ntp

Volume at ntp= 44.8