Question

if tan theta=a/b then a sin theta + b cos theta / a sin theta - b cos theta is equal to ______

Answer 1

Tan θ = a/b
sinθ/cosθ = a/b------(1)
lhs = (a sinθ- b cos θ)/(a sinθ + b cosθ)
= (asinθ/cosθ - bcosθ/cosθ)/(asinθ/cosθ+ bcosθ/cosθ)
dividing each term with cosθ
=(asinθ/cosθ-b/1)/(asinθ/cosθ+b/1)
=(a*a/b-b/1)/(a*a/b +b/1)
[from (1)]
= (a^2-b^2)/(a^2+b^2)

Answer 2

Answer:

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