Question

if tan theta = a/b, then find the value of a sin theta + b cos theta /a sin theta - b cos theta

Answer 1

Answer:

Step-by-step explanation:

Tan θ = a/b

sinθ/cosθ = a/b------(1)

lhs = (a sinθ- b cos θ)/(a sinθ + b cosθ)

= (asinθ/cosθ - bcosθ/cosθ)/(asinθ/cosθ+ bcosθ/cosθ)

dividing each term with cosθ

=(asinθ/cosθ-b/1)/(asinθ/cosθ+b/1)

=(a*a/b-b/1)/(a*a/b +b/1)

[from (1)]

= (a^2-b^2)/(a^2+b^2)......  ANSWER

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Answer 2

Answer:

here is right answer...........