If tan theta= a/b, then sin theta is?
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Answered by
2
Answer:
sin theta=a/root (a^2+b^2)
Step-by-step explanation:
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Answered by
1
Answer:
Tan¤ = sin¤/cos¤
then
Sin¤= Tan¤×Cos¤
tan¤ = P/B = a/b
Cos¤ = B/H
H = √(a²+b²) (by pythagoras theorem)
then
Sin¤ = a/b × b/√(a²+b²) = a/√(a²+b²)
Hop3 it helpsss
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