If tan theta=cos11+sin11/cos11-sin11 and theta is in the third quadrant, find theta
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44
answer is obtained as above
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LHS= cos11+sin11/cos11-sin11
divide both numerator and denominator by cos11
= 1+tan11/1- 1tan11
since tan 45=1 now we wil subtitute this value of 1 here in numerator
=tan45+tan11/1-tan45tan11 (since it is the formula for tan (a+b)so)
=tan(45+11)
=tan56
divide both numerator and denominator by cos11
= 1+tan11/1- 1tan11
since tan 45=1 now we wil subtitute this value of 1 here in numerator
=tan45+tan11/1-tan45tan11 (since it is the formula for tan (a+b)so)
=tan(45+11)
=tan56
AniDude09:
Hope this helps y'all.
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