if tan theta equal 20 by 21 show that 1 minus sin theta + cos theta by 1 + sin theta + cos theta equal 3 by 7
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Tanθ = 20/21
so, sinθ =20/29
cosθ = 21/29
now,
(1-sinθ+cosθ)/(1+sinθ + cosθ)
putting the values,
[1 - (20/29)+(21/29)]/[1 +(20/29)+(21/29)]
=(29-20+21)/(29+20+21)
=30/70
=3/7
please mark as BRAINLIEST please
so, sinθ =20/29
cosθ = 21/29
now,
(1-sinθ+cosθ)/(1+sinθ + cosθ)
putting the values,
[1 - (20/29)+(21/29)]/[1 +(20/29)+(21/29)]
=(29-20+21)/(29+20+21)
=30/70
=3/7
please mark as BRAINLIEST please
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