if tan theta is equal to 7 / 24 then find the value of P such that tan theta minus sin theta upon sin theta is equal to (- p / 28)
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tan = 7/24 = prependicular / base
prependicular = 7x and base = 24 X
hypo^2 = (7x) ^2 + (24x)^2
hypo ^2 = 625 X ^2
hypo = 25x
sin = prependicular / hypo = 7/25
sec = hypo / base = 25/24
according to question
(7/24)-(25/24)/(7/25 )= (7-25)/ 24 / (7/25)
= (-18/24)/(7/25)= (-3/4)*(25/7) = -75/28
by comparing
p = 75
prependicular = 7x and base = 24 X
hypo^2 = (7x) ^2 + (24x)^2
hypo ^2 = 625 X ^2
hypo = 25x
sin = prependicular / hypo = 7/25
sec = hypo / base = 25/24
according to question
(7/24)-(25/24)/(7/25 )= (7-25)/ 24 / (7/25)
= (-18/24)/(7/25)= (-3/4)*(25/7) = -75/28
by comparing
p = 75
bharat9291:
the question you typed is wrong
ok sir thanks
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Answer:
Complete the following activity to find sec 0 if tan 0 =7/24
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