If tan theta is equal to root 2 then find sin theta . cos theta
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tan theta =prpendicular/base =√2/1
then prpendicular=√2k
base=1k
hypotenuse=(√²k)²+(1k)²
=2k²+1k²
=3k²
now , sin theeta=prpendicular / hypotenuse
=√2k²/3k²
=√2/3
cos theeta=base/hypotenuse
=1k/3k
=1/3
choudharykanish:
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Answer:
tan theta =prpendicular/base =√2/1
then prpendicular=√2k
base=1k
hypotenuse=(√²k)²+(1k)²
=2k²+1k²
=3k²
now , sin theeta=prpendicular / hypotenuse
=√2k²/3k²
=√2/3
cos theeta=base/hypotenuse
=1k/3k
=1/3
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