If tan theta = p/q prove that p sin theta- q cos theta/p sin theta+ q cos theta=p^2-q^2/p^2+q^2
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tanA=p/q
then
sinA=p/√(p²+q²)
cosA=q/√(p²+q²)
=> (psinA-qcosA)/(psinA+qcosA)
= (p²-q²)/(p²+q²)
hope it helps you
then
sinA=p/√(p²+q²)
cosA=q/√(p²+q²)
=> (psinA-qcosA)/(psinA+qcosA)
= (p²-q²)/(p²+q²)
hope it helps you
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