Question

If tan theta=qsinα/p+qcosα then show hatt tan(α-theta)=psinα/q+pcosα

Answer 1

Steps:
1) Identities needed :
$\tan( \alpha - \beta ) = \frac{ \tan( \alpha ) - \tan( \beta ) }{1 + \tan( \alpha ) \times \tan( \beta ) }$

For Calculation see pic.