Factorise using identity:81-p4
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Answered by
1
81 - p^4
9^2 - ( p^2)^2
= (9+p^2)(9-p^2)
= (9+p^2)(3^2 - p)(3^2+p)
HOPE THIS HELPS YOU! ! ! !
9^2 - ( p^2)^2
= (9+p^2)(9-p^2)
= (9+p^2)(3^2 - p)(3^2+p)
HOPE THIS HELPS YOU! ! ! !
maxchristiano233:
very very thank you bro
Answered by
0
Here is your answer the following
81 - p^4
The next step is
9^2 - (p^2)^2
The next step is
Gives out
= (9 + p^2)(9 - p^2)
= (9 + p^2)(3^2 - p)(3^2 + p)
thank you please mark as brainliest
81 - p^4
The next step is
9^2 - (p^2)^2
The next step is
Gives out
= (9 + p^2)(9 - p^2)
= (9 + p^2)(3^2 - p)(3^2 + p)
thank you please mark as brainliest
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