if tan theta + sec theta =1. prove that sec theta = l2 + 1/2l
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Answer:
dose that help?
Step-by-step explanation:
tanθ+secθ=l
tanθ=l−secθ
squaring on both sides, we get,
tan
2
θ=(l−secθ)
2
sec
2
θ−1=l
2
+sec
2
θ−2lsecθ
l
2
−2lsecθ=−1
l
2
+1=2lsecθ
⇒secθ=
2l
l
2
+1
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