If tan theta + sec theta = l, then prove that sec theta = l^2 + 1/ 2l
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Answered by
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HERE IS YOUR ANSWER GOES LIKE THIS :
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YOUR QUESTION:
If tanФ+secФ=∫ then show that secФ=∫²+1/2∫
ANSWER:
tanФ+secФ=∫
tanФ=secФ
squaring on both sides
tan ²Ф=(∫-secФ)²
tan²Ф=∫²-2∫secФ+sec²Ф
sec²Ф-1=∫²-2∫secФ+sec²Ф
∫²-2∫secФ+1=0
secФ=∫²+1/2∫
===============================================================================================
❤️I HOPE THIS WILL HELP YOU ❤️
HAVE A GREAT DAY AHEAD✌️✌️
^_^
HERE IS YOUR ANSWER GOES LIKE THIS :
=====================================================================================
YOUR QUESTION:
If tanФ+secФ=∫ then show that secФ=∫²+1/2∫
ANSWER:
tanФ+secФ=∫
tanФ=secФ
squaring on both sides
tan ²Ф=(∫-secФ)²
tan²Ф=∫²-2∫secФ+sec²Ф
sec²Ф-1=∫²-2∫secФ+sec²Ф
∫²-2∫secФ+1=0
secФ=∫²+1/2∫
===============================================================================================
❤️I HOPE THIS WILL HELP YOU ❤️
HAVE A GREAT DAY AHEAD✌️✌️
^_^
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