if tan theta + sin theta equals to M and Express 4 tan theta sin theta in terms of m and n
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Let a be the first term and d be the common difference of the given A.P. Then,
Sm=n
⟹2m{2a+(m−1)d}=n
⟹2am+m(m−1)d=2n ...(i)
and, Sn=m
⟹2n{2a+(n−1)d}
⟹2an+n(n−1)d=2m ...(ii)
Subtracting equation (ii) from equation (i), we get
2a(m−n)+{m(m−1)−n(n−1)}d=2n−2m
⟹2a(m−n)+{(m2−n2)−(m−n)}d=−2(m−n)
⟹2a+(m+n−1)d=−2 [On dividing both sides by (m−n)] ...(iii)
Now,
Sm+n=2m+n{2a+(m+n−1)d}
⟹Sm+n=2m+n(−2) [Using (iii)]
⟹Sm+n=−(m+n)
Step-by-step explanation:
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