Question

If tan theta + sin theta =m and tan theta - sin theta = n then ( m² - n²) = ?​

Answer 1

Answer :

$( \tan0 + \sin0 ) {}^{2} - ( \tan0 - \sin0) \\ \tan {}^{2}0 + \sin {}^{2}0 + 2 \sin0 \tan0 - ( tan {}^{2}0 + \sin {}^{2}0 - 2 \sin0 \tan0 ) \\ tan {}^{2}0 + \sin {}^{2}0 + 2 \sin0 \tan0 - tan {}^{2}0 - \sin {}^{2}0 + 2 \sin0 \tan0 \\ 4 \sin0 \tan 0 \\ 4 \times \sin0 \times \frac{ \sin0 }{ \cos0 } \\ 4 \frac{ \sin {}^{2} 0 }{ \cos0 }$

I hope this will help u