if tan thita +cot thita =5 find the value of tan^2thita +cot^2thita
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here is ur answer mate !!!
tan theta + cot theta = 5
squaring both sides
(tan theta + cot theta) ^2 = 25
tan square theta + cot square theta + 2 tan theta × cot theta = 25
(by using (a+b)^2=a^2 +b^2 + 2ab)
tan sq theta + cot sq theta + 2×1 = 25
(bcz tan theta × cot theta = 1)
tan sq theta + cot sq theta +2 =25
tan sq theta + cot sq theta = 25-2
tan sq theta + cot sq theta = 23
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