if tan x =-4/3, find the vakue if 9 sec^2 x -4 cot x
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Answer:
13
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Tan X =-4/3
SinX/cosX=-4/3
Then sinX=-4 , cosX=3
9sec²X-4cotX=?
=9(1/cosX)²-4(cosX/sinX)
=9(1/3)²-4(3/-4)
=9(1/9)-(-3)
=1+3
=4
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Yours sincerely sathvik(HV SNIPER)
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