Question

if tan x=8/3, find sin x=?

Answer 1

tan theta =perpendicular upon base

perpendicular is 8 and base is 3

Using Pythagoras theorem

(H) ^2=(P) ^2+(B) ^2

H =√(8)^2+(3)^2

H= √73

sin theta is perpendicular upon hypotenuse

sin theta=8/√73

Answer 2

Answer:

sinx=8/√73

Step-by-step explanation:

8²+3²=√73