If tan x is 1÷ √3, find cos x - sin x, such that 0° ≤ x ≤ 90°
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Answer:
(root3-1)/2
Step-by-step explanation:
since tan x=1/root3
tan x=tan 30°
x=30°......... [where 0° ≤ x ≤ 90°]
therefore cos x-sin x=cos 30° -sin 30°
=(root3)/2-1/2
=(root3-1)/2
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