Math, asked by kapilmaurya9238, 3 months ago

If tan x is 1÷ √3, find cos x - sin x, such that 0° ≤ x ≤ 90°

Answers

Answered by devika862
1

Answer:

(root3-1)/2

Step-by-step explanation:

since tan x=1/root3

tan x=tan 30°

x=30°......... [where 0° ≤ x ≤ 90°]

therefore cos x-sin x=cos 30° -sin 30°

=(root3)/2-1/2

=(root3-1)/2

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