Question

if tan0=3/4, then 4sin0-cos0/4sin0+cos0

Answer 1

tan0=3/4=p/b

now,

h²=p²+b²

h²=(3)²+(4)²

h²=9+16

h²=25

h=5

again,

sin0=p/h=3/5

cos0=b/h=4/5

now putting sin and cos in given eqⁿ

4sin0-cos0/4sin0+cos0

4*3/5-4/5/4*3/5+4/5

12/5-4/5/12/5+4/5

8/5/16/5

8/16=1/2

hence, 1/2 is ur ans.