If tan0=4/3 find the value of 5sin0+2cos0/3sin0‐ cos0
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Answer:
39/10
Explanation:
as tan0=4/3=P/B
so P=4 and B=3
Now using Pythagoras theorem
P.sq +B.sq =H.sq
4×4+3×3=H.sq
H.sq=16+9
H=5
now putting these values in given eq..
5×4/5+2×3/5/3×4/5- 3/5
4+6/5×5/12-3/5
4+6/12-3/5
4+1/2-3/5
40+5-6/10
39/10
hence it solved
so easyyyy......!!!!!
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