Question

if tan0 = m/n,show that m sin0 -n cos0/m sin 0+n cos0 = m2-n2/m2+n2​

Answer 1

tanO=m/n

secO = √m²+n²/n

cos=n/√m²+n²

sinO= m/√m²+n²

lhs

m sinO-n cosO/ mSinO + ncosO

=(m²+n²/m²+n²)/(m²-n²/m²+n²)

=m²-n²/m²+n²

lhs =rhs proved

plz mark me as the brainliest