if tan2 45°- cos2 30°=xsin45°cos45° then find x
Answers
Answered by
144
tan²45° -cos²30°= xsin45°.cos45°
we know,
tan45 = 1
cos30° =√3/2
sin45° = 1/√2
cos45°= 1/√2
now,
1 - (√3/2)² = x(1/√2)(1/√2) = x/2
1 -3/4 = x/2
1/4 = x/2
x = 1/2
we know,
tan45 = 1
cos30° =√3/2
sin45° = 1/√2
cos45°= 1/√2
now,
1 - (√3/2)² = x(1/√2)(1/√2) = x/2
1 -3/4 = x/2
1/4 = x/2
x = 1/2
Answered by
31
Answer: x=1/2
Explanation: we know that,
tan45 = 1
cos30° =√3/2
sin45° = 1/√2
cos45°= 1/√2
now,
1 - (√3/2)² = x(1/√2)(1/√2)
= x/2
1 -3/4 = x/2
1/4 = x/2
x = 1/2
Hope this helps
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