If tan2A=cot(A-18), where 2A is an acute angle, find the value of A?
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tan 2A = cot(A-18)
tan2A=tan{90-(A-18)}
2A=90-A+18
3A=108
A=36
tan2A=tan{90-(A-18)}
2A=90-A+18
3A=108
A=36
Sohansrikanth:
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Answered by
1
A=36 ok
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