Question

if tan2A =cot(A–18°)where 2A is a positive acute angle,let us find the value of A .​

Answer 1

Holå mate❤

ANSWER✍

Tan2A=cot(A–18°)

or, cot (90°–2A) = cot (A–18°)[Cot (90°–∅) = tan∅]

or,90°–2A=A–18°

or,–2A–A=–90°–18°

or,–3A=–108°

=> A =36° (Ans)

✌hope it's help you✌

Answer 2

SOLUTION

=)tan 2A=cot(A-18°)

=)cot(90°-2A)=cot(A-18°)

=)90°-2A=A-18°

=)-3A= -108°

=)A= 108/3

=) A=36°

hope it helps