If tan2B = cot3B find B.
BrainlyHelper:
please take a note that, B is acute angle.
not Mentioned
OK If it is acute then too B = 54° satisfy
still Incomplete.
Answers
Answered by
0
Given,
tan2B = cot3B
We know that, tanx = cot( 90 - x)
Now,
cot ( 90 - 2B) = cot3B
Cancelling cotangent on both sides .
90 - 2B = 3B
90 = 5B
B= 18°
Also, We know cotx = tan( 90 - x)
tan2B= tan( 90 - 3B )
Cancelling tan on both sides.
2B= 90 - 3B
-90 = -5B
B = 18°
Hope helped!
tan2B = cot3B
We know that, tanx = cot( 90 - x)
Now,
cot ( 90 - 2B) = cot3B
Cancelling cotangent on both sides .
90 - 2B = 3B
90 = 5B
B= 18°
Also, We know cotx = tan( 90 - x)
tan2B= tan( 90 - 3B )
Cancelling tan on both sides.
2B= 90 - 3B
-90 = -5B
B = 18°
Hope helped!
This is incomplete answer as there exists other values of B too.
B = 54° also satisfy.
Try to give the answer in general form.
Answered by
7
Hey mate !!!
given , tan 2B = Cot 3B
now , tan2(90-B) =. Cot 3B
=> Cot( 90 - 2B) = Cot 3B
cancelling of Cot
we get 5B = 90 °
B = 18°
hope it helps:D
thanks
given , tan 2B = Cot 3B
now , tan2(90-B) =. Cot 3B
=> Cot( 90 - 2B) = Cot 3B
cancelling of Cot
we get 5B = 90 °
B = 18°
hope it helps:D
thanks
This is incomplete answer.
There exists other values of B that satisfy the given condition.
Sorry, but try to give the answer in more general form.
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