if tanA=0.4 then sin2A=?
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Answered by
2
tanA=4/10
therefore
sinA=2/(29^1/2)
cosA=5/(29^1/2)
sin2A=2cosAsinA
sin2A=2×10/29
sin2A=20/29
therefore
sinA=2/(29^1/2)
cosA=5/(29^1/2)
sin2A=2cosAsinA
sin2A=2×10/29
sin2A=20/29
Answered by
1
sin2A=2tanA/(1+tan^2A)(refer ncert XI)
=> sin2A=2*0.4/(1+0.4^2)
=>sin2A=0.8/1.16=0.689655172
=> sin2A=2*0.4/(1+0.4^2)
=>sin2A=0.8/1.16=0.689655172
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