Question

If tanA=1/2 and tanB=1/3,Then Prove That: A+B=45Degree.

Answer 1

heya yor answer is here ________
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We know that Tan(A+B) = (TanA + TanB) / (1 - TanA.TanB)

                                           = (1/2  +  1/3) / (1 - (1/2)(1/3) )

                                           = (3+2 / 6)  / ( 6-1  / 6)

                                           = (5/6)  /  (5/6)    =   1

 

As Tan 45o = 1 = Tan(A+B)

Hence A+B = 45o

Answer 2

tan(A+B)={(tanA+tanB)/(1-(tanA×tanB))}
={(1/2+1/3)/(1-(1/2×1/3))}
={(5/6)/(1-(1/6))}
={(5/6)/(5/6)}
tan(A+B)=1
A+B=tan^(-1)(1)=45 degree