if tanA=1/2 find the value of cosA/sinA+sinA/1+cosA
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given tanA=1/2
now ,cotA=cos A/sinA
=1/tanA
=1/1/2
=2/1
cosA/SinA=2/1
therefore cos A=2 and. sinA=1
therefore =cosA/sinA+sinA/1+cosA
now putting value of sinA=1 andcisA=2
= 2/1 + 2/1+1
=2+2/2
=2+1
= 3
so. cosA/sinA+sinA/1+cosA=3
now ,cotA=cos A/sinA
=1/tanA
=1/1/2
=2/1
cosA/SinA=2/1
therefore cos A=2 and. sinA=1
therefore =cosA/sinA+sinA/1+cosA
now putting value of sinA=1 andcisA=2
= 2/1 + 2/1+1
=2+2/2
=2+1
= 3
so. cosA/sinA+sinA/1+cosA=3
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