If tanA=1/2,tanB=1/3, then tan(2A+B)is equal to
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formula used :
tan(A+B)= (tanA+tanB)/ (1-tanA tan B)
tan2A= 2tanA / 1-tan^2A
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hope this will help you....
tan(A+B)= (tanA+tanB)/ (1-tanA tan B)
tan2A= 2tanA / 1-tan^2A
--------------------------------------------------------------------------------------------------
hope this will help you....
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hope it helps u
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