Question

If tanA= 1/2 , tanB=1/3. Using tan (A+B)= tanA
+tan B/1-tanA +tanB, Prove that (A+B)=45

Answer 1

Given tanA = 1/2   and tanB = 1/3
 we know that 
tan(A+B) = (tanA + tanB)/1-tanA*tanB
tan(A+B) = (1/2+1/3)/(1-1/2*1/3)
               =(5/6)/(1-1/6)
             = (5/6)/(5/6)
              =1
tan (A+B)=tan 45                          ( since tan 45 = 1)
therefore A+B= 45

Answer 2

Answer:

It is proved that $A+B=45$

Step by Step Explanation:

As we know     $tan(A+B) = \frac{ tanA + tanB}{1 - tanAtanB}$

Step 1:

Given that     $tanA = \frac{1}{2}$    and   $tanB = \frac{1}{3}$

$tan(A+B) =$   $\frac{ tanA + tanB}{1 - tanAtanB}$

                  $={\Large } \frac{\frac{1}{2} + \frac{1}{3} }{1-\frac{1}{2} \frac{1}{3} }$

                  $=\frac{5}{6} /\frac{5}{6}$

                   $=1$

Step 2:

$\therefore$$A+B = 45$

Hence proved.

#SPJ2