If TanA=1/2,then sin2A+cos2A=?
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Step-by-step explanation:
we have given, tanA=1/2
we know that,
Sin2A=2tanA/(1+tan²A)
Cos2A={(1-tan²A) /(1+tan²A) }
Hence, Sin2A =2(1/2)/(1+(1/2)²)
= 4/(1+5) = 4/5
Cos2A =( 1- (1/2)²)/(1+(1/2)²)
= (1-(1/4))/(1+(1/4))
= {[(4-1)/4]/[(4+1)/4]} = 3/5
sin2A+cos2A =( 4/5 ) + (3/5 )
= 7/5
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