If tanA=12/5 then find the value of 1+sinA/1-sinA
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According to the question, Given that:
- tanA = 12/5
We need to find the value of:
- 1+sinA/1-sinA
We know that,
- tanA = 12/5
Where,
- Perpendicular = 12k
- Adjacent Side = 5k
Finding Hypotenuse by Pythagoras Theorm:
⠀⠀⇒(AC)² = (BC)²+(AB)²
⠀⠀⇒AC² = (12k)²+(5k)²
⠀⠀⇒AC² = 144k²+25k²
⠀⠀⇒AC² = 169k²
⠀⠀⇒AC = √169k²
⠀⠀⇒AC = 13k
We know that sinA,
- sinA = Perpendicular/Hypotenuse
- sinA = 12k/13k
- sinA = 12/13
Now, according to the question, substitute:
⠀⠀⇒1+sinA/1-sinA
⠀⠀⇒(1+12/13)/(1-12/13)
⠀⠀⇒(13+12/13)/(13-12/13)
⠀⠀⇒(25/13)/(1/13)
⠀⠀⇒25 [13 gets cancelled]
Hence, Solved.
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