Question

If tanA=12/5 then find the value of 1+sinA/1-sinA​

Answer 1

Answer:

hope it's helpful to you!!!!!

Answer 2

According to the question, Given that:

• tanA = 12/5

We need to find the value of:

• 1+sinA/1-sinA

We know that,

• tanA = 12/5

Where,

• Perpendicular = 12k
• Adjacent Side = 5k

Finding Hypotenuse by Pythagoras Theorm:

⠀⠀⇒(AC)² = (BC)²+(AB)²

⠀⠀⇒AC² = (12k)²+(5k)²

⠀⠀⇒AC² = 144k²+25k²

⠀⠀⇒AC² = 169k²

⠀⠀⇒AC = √169k²

⠀⠀⇒AC = 13k

We know that sinA,

• sinA = Perpendicular/Hypotenuse

• sinA = 12k/13k

• sinA = 12/13

Now, according to the question, substitute:

⠀⠀⇒1+sinA/1-sinA

⠀⠀⇒(1+12/13)/(1-12/13)

⠀⠀⇒(13+12/13)/(13-12/13)

⠀⠀⇒(25/13)/(1/13)

⠀⠀⇒25 [13 gets cancelled]

Hence, Solved.