If tanA=12/5,then find the value of sinA+cosA
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Step-by-step explanation:
tanA = opposite/adjacent
= 12x/5x
hypotenuse = opposite^2 + adjacent^2
= (12x)^2 + (5x)^2
= 144x^2 + 25x ^2
=169x^2
hypotenuse = 13x
sinA=opposite/hypotenuse
= 12x/13x
= 12/13
cosA=adjacent/hypotenuse
=5x/13x
=5/13
sinA+cosA = 12/13 + 5/13
=17/13
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