Math, asked by adityavardhankp9uh3t, 1 year ago

if tanA = 3÷4 show that sinAcosA = 12÷25

Answers

Answered by Panzer786
0
Heya !!!




TanA = 3/4 = P/B




P = 3. and B = 4




By pathagarous theorem , we have



(H)² = (B)² + (P)²




(H)² = (4)² + (3)²






H = root 25



H = 5



Therefore,



SinA = P/H = 3/5




And,



CosA = B/H = 4/5







---------------------------------------------





SinA × Cos A = 12/25






LHS = SinA × CosA




=> 3/5 × 4/5





=> 12/25




Hence,



LHS = RHS.....PROVED.....







★ ★ ★ HOPE IT WILL HELP YOU ★ ★ ★
Answered by TheAishtonsageAlvie
7

 \bf \: Hello  \:there

• Given :-

 \tan( \theta)  =  \frac{3}{4}  \\  \\ we \: know \: \\  \\  \boxed{ tan\theta =  \frac{p}b  }
By Pythagoras theorem -

H² = P²+B²

H = √(3²+4²) = 5

Now according to the question -
sin \theta.cos \theta =  \frac{12}{25}   \\   \\ \Rightarrow \frac{3}{5}  \times  \frac{4}{5}  =  \frac{12}{25}  \\  \\ \Rightarrow  \frac{12}{25}  =  \frac{12}{25}

Hope this helps you ☺
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