if tanA = 3÷4 show that sinAcosA = 12÷25
Answers
Answered by
0
Heya !!!
TanA = 3/4 = P/B
P = 3. and B = 4
By pathagarous theorem , we have
(H)² = (B)² + (P)²
(H)² = (4)² + (3)²
H = root 25
H = 5
Therefore,
SinA = P/H = 3/5
And,
CosA = B/H = 4/5
---------------------------------------------
SinA × Cos A = 12/25
LHS = SinA × CosA
=> 3/5 × 4/5
=> 12/25
Hence,
LHS = RHS.....PROVED.....
★ ★ ★ HOPE IT WILL HELP YOU ★ ★ ★
TanA = 3/4 = P/B
P = 3. and B = 4
By pathagarous theorem , we have
(H)² = (B)² + (P)²
(H)² = (4)² + (3)²
H = root 25
H = 5
Therefore,
SinA = P/H = 3/5
And,
CosA = B/H = 4/5
---------------------------------------------
SinA × Cos A = 12/25
LHS = SinA × CosA
=> 3/5 × 4/5
=> 12/25
Hence,
LHS = RHS.....PROVED.....
★ ★ ★ HOPE IT WILL HELP YOU ★ ★ ★
Answered by
7
• Given :-
By Pythagoras theorem -
H² = P²+B²
H = √(3²+4²) = 5
Now according to the question -
Hope this helps you ☺
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