if tanA = √3 then find sinA.cosC+cosA.sinC
ansss:
are angle C and angle A complementary
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give that
tan a = √3
tan a = tan 60
a = 60
we know that
sum of all sides are 180
than
∠a + ∠b + ∠c = 180
60 + 90 + ∠c = 180
∠c = 180-150
∠c = 30
in the trignometry there is one formula
that is
sin(a+c) = sin a × cos c + cos a × sin c
then
sin 60 × cos 30 + cos 60 × sin 30 = sin (60 + 30)
= sin 90
= 1.
tan a = √3
tan a = tan 60
a = 60
we know that
sum of all sides are 180
than
∠a + ∠b + ∠c = 180
60 + 90 + ∠c = 180
∠c = 180-150
∠c = 30
in the trignometry there is one formula
that is
sin(a+c) = sin a × cos c + cos a × sin c
then
sin 60 × cos 30 + cos 60 × sin 30 = sin (60 + 30)
= sin 90
= 1.
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