If tanA=√3, verify that sec²A–tan²A=1
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tanA= tan 60°
A= 60°
LHS
. sec ^2 60° - tan^ 2 60°
=. ( 2)^ 2 - ( root 3) ^ 2
= 4 - 3
= 1 RHS PROVED
A= 60°
LHS
. sec ^2 60° - tan^ 2 60°
=. ( 2)^ 2 - ( root 3) ^ 2
= 4 - 3
= 1 RHS PROVED
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