if+tanA=4/3,then+(sinA++Cos+A)=?
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Step-by-step explanation:
tan A =4/3
tanA=opposite/adjacent =4/3
so, according to Pythagoras theorem
(AB)square+(BC) square= (AC)square
so,AC=hypotenuse=5
sinA=opposite/hypotenuse=4/5
cosA=adjacent/hypotenuse=3/5
now,sinA+cosA=4/5+3/5=7/5
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