If tanA=4/7
(7sinA-3cosA)÷(7sinA+2cosA)=?
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1
tanA=4/7
sinA/cosA=4/7
(7×4-3×7)÷(7×3+2×7)
(28-21)÷(21+14)
7÷35
1/5
✍️✍️ please mark it brainlist answer.....
tanayaakkalkote18945:
The correct answer is 1/6
Answered by
2
(7 sinA -3 cosA )/(7sinA +2cosA )
dividing by cos A in numerator and denominator:-
(7tanA -3 )/ (7tanA +2)
(7×4/7 - 3) /(7×4/7 + 2)
(4-3)/(4+2)
1/6
oh
ohh...how
tell me
ya...i know
i didn't get ur process
how this can be......ur answer is also right and mine is also right
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