Question

If tanA=4/7
(7sinA-3cosA)÷(7sinA+2cosA)=?​

Answer 1

tanA=4/7

sinA/cosA=4/7

(7×4-3×7)÷(7×3+2×7)

(28-21)÷(21+14)

7÷35

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Answer 2

(7 sinA -3 cosA )/(7sinA +2cosA )

dividing by cos A in numerator and denominator:-

(7tanA -3 )/ (7tanA +2)

(7×4/7 - 3) /(7×4/7 + 2)

(4-3)/(4+2)

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