Question

If tanA= b/a where a and b are real numbers find value of Sin^2A.​

Answer 1

Answer:

sin 2A=2 sin A cosA

=2 ×b×a

sin 2A=2ab

Step-by-step explanation:

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Answer 2

Tan theta= perpendicular/ base

Given Tan A=b/a

Then
Perpendicular =b

Base = a

Pythagoras Theorem

Hypotenuse^2=Base^2+Perpendicular^2

Hypotenuse^2=a^2+b^2

Hypotenuse = square roots a^2+b^2

Sin A= Perpendicular/hypotenuse

Sin A= b/square roots a^2+b^2

Squaring both sides

Sin^2A= b^2 /a^2+b^2

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