If tanA-cotA=1 then tan2A+cot2A is?
Answers
Answered by
12
Heya..!!!
GIVEN that:-
TanA - cotA = 1
[On squaring both side]
we get,
Tan²A + cot²A - 2tan×1/tanA = 1
tan²A + cot²A = 1 + 2
Tan²A + cot²A = 3
I HOPE ITS HELP YOU
GIVEN that:-
TanA - cotA = 1
[On squaring both side]
we get,
Tan²A + cot²A - 2tan×1/tanA = 1
tan²A + cot²A = 1 + 2
Tan²A + cot²A = 3
I HOPE ITS HELP YOU
Answered by
4
Hi ,
It is given that ,
tan A - cot A = 1 ---- ( 1 )
Do the square of equation ( 1 ) ,
we get ,
( tan A - cot A )² = 1
tan² A + cot² A - 2tan A cotA = 1
tan² A + cot² A - 2 = 1
[ Since tanA cotA = 1 ]
tan² A + cot² A = 1 + 2
tan² A + cot² A = 3
I hope this helps you.
: )
It is given that ,
tan A - cot A = 1 ---- ( 1 )
Do the square of equation ( 1 ) ,
we get ,
( tan A - cot A )² = 1
tan² A + cot² A - 2tan A cotA = 1
tan² A + cot² A - 2 = 1
[ Since tanA cotA = 1 ]
tan² A + cot² A = 1 + 2
tan² A + cot² A = 3
I hope this helps you.
: )
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