Question

If tanA + CotB = 2, A = 450 and B is an acute angle, then find the value of B

URGENT

Answer 1

Answer:

B = 1

Step-by-step explanation:

we know that

we know that Tan(90°-A)=CotA

we know that Tan(90°-A)=CotA we substitute the value of tanA

we know that Tan(90°-A)=CotA we substitute the value of tanA Here, Tan(90°-A)+CotB = 2

we know that Tan(90°-A)=CotA we substitute the value of tanA Here, Tan(90°-A)+CotB = 2 CotA + CotB = 2

we know that Tan(90°-A)=CotA we substitute the value of tanA Here, Tan(90°-A)+CotB = 2 CotA + CotB = 2 Cot(A+B) = 2

we know that Tan(90°-A)=CotA we substitute the value of tanA Here, Tan(90°-A)+CotB = 2 CotA + CotB = 2 Cot(A+B) = 2 we know that A=45° and value of 45°=1

we know that Tan(90°-A)=CotA we substitute the value of tanA Here, Tan(90°-A)+CotB = 2 CotA + CotB = 2 Cot(A+B) = 2 we know that A=45° and value of 45°=1 Cot(1+B) = 2

we know that Tan(90°-A)=CotA we substitute the value of tanA Here, Tan(90°-A)+CotB = 2 CotA + CotB = 2 Cot(A+B) = 2 we know that A=45° and value of 45°=1 Cot(1+B) = 2 CotB = 2-1

we know that Tan(90°-A)=CotA we substitute the value of tanA Here, Tan(90°-A)+CotB = 2 CotA + CotB = 2 Cot(A+B) = 2 we know that A=45° and value of 45°=1 Cot(1+B) = 2 CotB = 2-1 CotB = 1

we know that Tan(90°-A)=CotA we substitute the value of tanA Here, Tan(90°-A)+CotB = 2 CotA + CotB = 2 Cot(A+B) = 2 we know that A=45° and value of 45°=1 Cot(1+B) = 2 CotB = 2-1 CotB = 1 The value of B is 1

we know that Tan(90°-A)=CotA we substitute the value of tanA Here, Tan(90°-A)+CotB = 2 CotA + CotB = 2 Cot(A+B) = 2 we know that A=45° and value of 45°=1 Cot(1+B) = 2 CotB = 2-1 CotB = 1 The value of B is 1 #Hope you have help this#

we know that Tan(90°-A)=CotA we substitute the value of tanA Here, Tan(90°-A)+CotB = 2 CotA + CotB = 2 Cot(A+B) = 2 we know that A=45° and value of 45°=1 Cot(1+B) = 2 CotB = 2-1 CotB = 1 The value of B is 1 #Hope you have help this# #Thank You#