Question

If tanA = cotB, prove that A + B = 90, where A and B are measures of acute angles.

Answer 1

we know the concepts tan(90°–θ ) = cotθ
tanA = cotB

⇒ tanA = tan(90°–B)

⇒ A = 90° –B

⇒ A + B = 90°

hence, it is proved that if tanA = cotB ,then A + B = 90° , where A and B are measures of acute angles .

Answer 2

HELLO DEAR,

we know that:- tan(90°–x ) = cotx

given:- tanA = cotB

so, tanA = tan(90 - B)

A = (90 - B)

A + B = 90

hence, A + B = 90, where A and B are measures of acute angles.

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