Question

if tanA​+secA=2/3 then tanA-secA=

A)3/2
B)-2/3
C)-2/5
D)-3/2​

Answer 1

Answer:

D) -3/2

Step-by-step explanation:

given

tanA+secA=2/3

now multiply tanA-secA on both sides

(tanA+secA) (tanA-secA) =2/3(tanA-secA)

tan^2 A - sec^2 A=2/3(tanA-secA)

we know that sec^2 A - tan^2 A= 1

so...

-1=2/3(tanA-secA)

tanA-secA= -3/2