If tanB + cot B = 5, then tan²B+ cot² B is (a) 5 (b) 23 (c) 25 (d) 27
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Answer:
(tan + cot)² = tan² + 2tan•cot + cot²
(5)² = tan² + 2 + cot²
25 = tan² + 2 + cot²
23 = tan² + cot²
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