If tangents ab and ac inclined to each other at an angle of 120 are drawn to a cirle with centre o of radius 6cm and then find the length of each tangent
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in this we see that OCB is a right angle triangle
so, angle obc = 60°
tan 60° = √3 = OC/CB
√3 = 6/CB
CB = 6/√3 = 2√3
hence, length of tangent = 2√3 cm.
so, angle obc = 60°
tan 60° = √3 = OC/CB
√3 = 6/CB
CB = 6/√3 = 2√3
hence, length of tangent = 2√3 cm.
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