If tanø=-2.0145 when0<ø<2pi then find ø
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tan∅ = -2.0145
∅ =nπ + tan-¹(-2.0145)
= nπ - tan-¹( 2.0145)
put n = 1
∅ = π - tan-¹( 2.0145)
and put n = 2
∅ = 2π - tan-¹( 2.0145)
hence two value possible in [ 0, 2π ]
∅ =nπ + tan-¹(-2.0145)
= nπ - tan-¹( 2.0145)
put n = 1
∅ = π - tan-¹( 2.0145)
and put n = 2
∅ = 2π - tan-¹( 2.0145)
hence two value possible in [ 0, 2π ]
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