Math, asked by trigo1, 1 year ago

If tanx=1/root7 then cosec^2

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Answered by TPS
0
tanx= \frac{1}{ \sqrt{7} } \\cotx= \frac{1}{tanx}= \sqrt{7}  \\\ \\we\ know\ that\ \\cosec^2x-cot^2x=1\\ \Rightarrow cosec^2x-( \sqrt{7} )^2=1\\ \Rightarrow cosec^2x-7=1\\ \Rightarrow cosec^2x=1+7\\ \Rightarrow cosec^2x=\boxed8
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